Q.
A charged particle of mass m=1g and charge q=1μC enters along AB at point A in a uniform magnetic field B=1.2 T existing in the rectangular region of size a×b, where a=4m and b=3m. The particle leaves the region exactly at corner point C. What is the speed v(in m s-1 )of the particle?
see full answer
Want to Fund your own JEE / NEET / Foundation preparation ??
Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya
answer is 5.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Let speed of the particle is v (speed will remain constant)r=AO=CO=mvqB also ar=sinθ,r-br=cosθSolve the above equation to getv=qBa2+b22mb=10-6×1.242+322×10-6×3=5 m/s
Watch 3-min video & get full concept clarity