Questions
A charged particle moves in a uniform magnetic field perpendicular to it, in a circle of radius of 4 cm. On passing through a metallic sheet it loses half of its kinetic energy. Then, the radius of curvature of the particle is
detailed solution
Correct option is D
R=mvqB=mqB2(KE)m=2mqBKE⇒ R1R2=KEKE/2⇒R2=R12=42=22 cmTalk to our academic expert!
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