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Q.

A charged particle moves in a uniform magnetic field perpendicular to it,   in a  circle of radius of  4 cm. On passing through a metallic sheet it loses half of its kinetic energy. Then, the radius of curvature of the particle is

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a

2 cm

b

4 cm

c

8 cm

d

22 cm

answer is D.

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Detailed Solution

R=mvqB=mqB2(KE)m=2mqBKE⇒  R1R2=KEKE/2⇒R2=R12=42=22 cm
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