A charged particle moves in a uniform magnetic field perpendicular to it, with a radius of curvature 4 cm. On passing through a metallic sheet it loses half of its kinetic energy. Then, the radius of curvature of the particle is

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2 cm

4 cm

8 cm

22 cm

answer is D.

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Detailed Solution

r=mvqB=m2KmqBFrom the above relation we get, r2=r12

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