A charged particle moves with velocity v→$$=ai^+dj^$$ in a magnetic field B→$$=Ai^+Dj^$$. The force acting on the particle has magnitude F. Then,

Correct option is 1F=0, if aD =dA.

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A charged particle moves with velocity $\vec{v} = a \hat{i} + \hat{d j}$ in a magnetic field $\vec{B} = \hat{A i} + D \hat{j}$ . The force acting on the particle has magnitude F. Then,

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F=0, if aD =dA.

F=0, if aD =-dA.

F=0, if aA =-dD.

F∝a2+b21/2×A2+D21/2

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detailed solution

Correct option is A

IF Velocity of charge and magnetic field vectors are parallel then force acting on the charged particle is zero. then aA=dD

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A charged particle moves with velocity v→=ai^+dj^ in a magnetic field B→=Ai^+Dj^. The force acting on the particle has magnitude F. Then,

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Ready to Test Your Skills?

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A charged particle moves with velocity $\vec{v} = a \hat{i} + \hat{d j}$ in a magnetic field $\vec{B} = \hat{A i} + D \hat{j}$ . The force acting on the particle has magnitude F. Then,