A charged particle moves with velocity v→ $$=$$ $$ai^+dj^$$ in a magnetic field B→ $$=$$ $$Ai^+Dj^$$ the force acting on the particle has magnitude F

Correct option is 1F = 0 if aD = Ad

Questions

A charged particle moves with velocity $\vec{v} = (a \hat{i} + d \hat{j})$ in a magnetic field $\vec{B} = (A \hat{i} + D \hat{j})$ the force acting on the particle has magnitude F

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F = 0 if aD = Ad

F = 0 if aD = –Ad

F = 0 if aA = –dD

F ∝ a2+d212×A2+D212

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detailed solution

Correct option is A

F→ ∝ v→ ×B→ ∝ aD−Adk^

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A charged particle moves with velocity v→ = ai^+dj^ in a magnetic field B→ = Ai^+Dj^ the force acting on the particle has magnitude F

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A charged particle moves with velocity $\vec{v} = (a \hat{i} + d \hat{j})$ in a magnetic field $\vec{B} = (A \hat{i} + D \hat{j})$ the force acting on the particle has magnitude F