A charged particle is projected with velocity v0 along positive x-axis. The magnetic field B is directed along negative z-axis between x = 0 and x = L. The particle emerges out (at x = L) at an angle of 60º with the direction of projection. Find the velocity with which the same particle were projected (at x = 0) along positive x-axis so that when it emerges out (at x = L), the angle made by it is 30º with the direction of projection
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a
2v0
b
v02
c
v03
d
V03
answer is D.
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Detailed Solution
In ∆OABAB = L = constantOB=r=mvqBsinθ=Lr⇒L=rsinθ=constant or vsinθ= constant v0sin60∘=v′sin30∘v′=3v0