Questions
A charged particle q is shot towards another charged particle Q which is fixed, with a speed . It approaches Q upto a closest distance r and then returns. If q were given a speed 2 , the closest distances of approach would be
detailed solution
Correct option is D
Charge q will momentarily come to rest at a distance r from charge Q when all it's kinetic energy converted to potential energy i.e. 12mv2=14πε0.qQrTherefore the distance of closest approach is given by r=qQ4πε0.2mv2⇒r∝1v2Talk to our academic expert!
Similar Questions
Kinetic energy of an electron accelerated through a potential difference of 100 V is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
