Q.
A charged particle q is shot towards another charged particle Q which is fixed, with a speed ν. It approaches Q upto a closest distance r and then returns. If q were given a speed 2ν , the closest distances of approach would be
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
r
b
2r
c
r/2
d
r/4
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Charge q will momentarily come to rest at a distance r from charge Q when all it's kinetic energy converted to potential energy i.e. 12mv2=14πε0.qQrTherefore the distance of closest approach is given by r=qQ4πε0.2mv2⇒r∝1v2
Watch 3-min video & get full concept clarity