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Q.

A charged particle of radius 5×10−7m is located in a horizontal electric field of intensity 6.28×105V/m. The surrounding medium has the coefficient of viscosity  η=1.6×105N−s/m2. The particle start moving under the effect of electric field and finally attains a uniform horizontal speed of  0.02 m/s. Find the _______×108 number of electrons on it. Assume gravity free space

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answer is 3000.00.

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Detailed Solution

When electric force and drag force balances each other , particle moves with uniform speed. ∴qE=6πηrv ⇒NeE=6πηrv ⇒N=6πηrveE ⇒N=6π×1.6×105×5×10−7×0.021.6×10−19×6.28×105 ⇒N=3000×108
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