A charged particle of specific charge qm=α is released from origin at time t=0 with velocity V¯=V0i^+j^ in uniform magnetic field B¯=B0i^. Co-ordinates of the particle at time t=πB0α are.
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a
v02B0α,2.v0αB0,−v0B0α
b
−v02B0α,0,0
c
0,2v0B0α,v0π2B0α
d
v0πB0α,0,−2v0B0α
answer is D.
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Detailed Solution
α=qm, Path of the particle will be a helix of time period T=2πmBoq=2πB0α The given time t=πB0α=T2∴ Coordinates of particle at time t=T2Would be VxT/2,0,−2rHere, r=mV0B0q=v0B0α ∴The coordinates are VoπB0α,0,−2V0Boα .
A charged particle of specific charge qm=α is released from origin at time t=0 with velocity V¯=V0i^+j^ in uniform magnetic field B¯=B0i^. Co-ordinates of the particle at time t=πB0α are.