A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is 9.6×10−16 kg, the charge on it and excess number of electrons on the particle are respectively (g=10 m/s2)
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a
4.8×10−19C, 3
b
5.8×10−19C, 4
c
3.8×10−19C, 2
d
2.8×10−19C, 1
answer is A.
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Detailed Solution
In equilibrium QE=mg⇒n=mgEe=9.6×10−16×1020,000×1.6×10−19=3charge 3e