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Q.

A charged particle of unit mass and unit charge moves with velocity of v→=(8i^+6j^)m/s in a magnetic field ofB→=2k^TChoose the correct alternative

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a

The path of the particle may bex2+y2−4x−21=0

b

The path of the particle may bex2+y2−4x−5=0

c

The path of the particle may be x2+y2+2x−8=0

d

The path of the particle may be x2+y2−2x−15=0

answer is A.

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Detailed Solution

r=mvqB=1×101×2=5m And motion of particle will be in x – y plane.
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