The charges on two sphere are +7μC and – 5μC respectively. They experience a force F. If each of them is given and additional charge of – 2μC, the new force of attraction will be

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F / 2

F/3

answer is A.

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Detailed Solution

F=14πε0+7×10−6−5×10−6r2=−14πε035×1012r2NF'=14πε0(+5×10−6)(−7×10−6)r2=−14πε035×1012r2N

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