First slide

Electrostatic force

Question

The charges on two sphere are +7 $μ$ C and – 5 $μ$ C respectively. They experience a force F. If each of them is given and additional charge of – 2 $μ$ C, the new force of attraction will be

Easy

A

F
B

F / 2
C

$F / \sqrt{3}$
D

2F

Solution

$F = \frac{1}{4 {πε}_{0}} \frac{(+ 7 \times 10^{- 6}) (- 5 \times 10^{- 6})}{r^{2}} = - \frac{1}{4 {πε}_{0}} \frac{35 \times 10^{12}}{r^{2}} N$
$F' = \frac{1}{4 {πε}_{0}} \frac{(+ 5 \times 10^{- 6}) (- 7 \times 10^{- 6})}{r^{2}} = - \frac{1}{4 {πε}_{0}} \frac{35 \times 10^{12}}{r^{2}} N$

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