A circuit containing capacitors $$C1$$ and $$C2$$ as shown in the figure are in steady state with key $$K1$$ closed and $$K2$$ is opened. At the instant t $$=$$ $$0$$, if $$K1$$ is opened and $$K2$$ is closed then the maximum current in the circuit will be :

Question

A circuit containing capacitors $$C1$$ and $$C2$$ as shown in the figure are in steady state with key $$K1$$ closed and $$K2$$ is opened. At the instant t $$=$$ $$0$$, if $$K1$$ is opened and $$K2$$ is closed then the maximum current in the circuit will be :

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When switch $$K1$$ is opened and $$K2$$ is closed it becomes L–C              circuit          so                     applying               energy conservation :Voltage across $$2$$μ$$f=10V$$∴$$12CV2=12Li2i=max$$  current  across  $$inductor=2$$×$$10$$−$$6$$×$$102=0.2$$×$$10$$−$$3$$×$$i2210=0.2$$ $$i2i=1$$ A

A circuit containing capacitors $C_{1}$ and $C_{2}$ as shown in the figure are in steady state with key $K_{1}$ closed and $K_{2}$ is opened. At the instant t = 0, if $K_{1}$ is opened and $K_{2}$ is closed then the maximum current in the circuit will be :

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A circuit containing capacitors C1 and C2 as shown in the figure are in steady state with key K1 closed and K2 is opened. At the instant t = 0, if K1 is opened and K2 is closed then the maximum current in the circuit will be :

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A circuit containing capacitors $C_{1}$ and $C_{2}$ as shown in the figure are in steady state with key $K_{1}$ closed and $K_{2}$ is opened. At the instant t = 0, if $K_{1}$ is opened and $K_{2}$ is closed then the maximum current in the circuit will be :