A circuit containing capacitors C1 and C2 shown in figure is in the steady state with key K1 closed. At the instant t = 0, K1 is opened and K2 is closed. The angular frequency of oscillation of the circuit and charge across C1 at t1=125μs are respectively

Angular frequency of oscillationω=1LC1=10.2×10-3×8×10-6=2.5×104rad/s=25×103rad/sQC1-Ldldt=0⇒QC1+Ld2Qdt2=0The solution of this equation is Q=Q0 sinωt+ϕWhere at t = 0, Q = Q0Q0=CeqV=C1C2C1+C2V=8×2×10-12×2010×10-6=32×10-6Cϕ=π2Q=(32μC) cos2.5×104×125×10-6=-32μC