First slide
Moving coil Galvanometer

A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm all connected in series. If the ammeter has a coil of resistance 480 ohm and a shunt of 20 ohm, the reading in the ammeter will be


The circuit shown in the figure.

Resistance of the ammeter is


 (As 480Ω and 20Ω are in parallel) 

 As ammeter is in series with 40.8Ω , 

   Total resistance of the circuit is 


By Ohm's law, 

Current in the circuit is 

I=VR=30 V60Ω=12 A=0.5 A

Thus the reading in the ammeter will be  0.5  A. 

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