First slide

Capacitors and capacitance

Question

In the circuit diagram shown in the adjoining figure, the resultant capacitance between $P$ and $Q$ is

Easy

A

$47 μ F$
B

$3 μ F$
C

$60 μ F$
D

$10 μ F$

Solution

The given circuit can be drawn as where $C = (3 + 2) μ F = 5 μ F$
$\frac{1}{C_{P Q}} = \frac{1}{5} + \frac{1}{20} + \frac{1}{12} = \frac{20}{60} = \frac{1}{3} \Rightarrow C_{P Q} = 3 μ F$

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