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In the circuit of figure, the source frequency is The current in the circuit will be
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a
2 A
b
3.3 A
c
2/5A
d
5A
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Correct option is A
XL=Lω=5×10-3×2000=10ΩXC=1Cω=150×10-6×2000=10010Ω=10ΩSince XL= XC therefore,Z=R=5.9+0.10+4=10ΩIv=EvZ=2010A=2A
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For the circuit shown in figure, the ammeter A2 reads 1.6 A and ammeter A3 reads 0.4 A. Then
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