In the circuit of figure, the source frequency is ω=2000 rad s-1 The current in the circuit will be

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2 A

3.3 A

2/5A

answer is A.

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Detailed Solution

XL=Lω=5×10-3×2000=10ΩXC=1Cω=150×10-6×2000=10010Ω=10ΩSince XL= XC therefore,Z=R=5.9+0.10+4=10ΩIv=EvZ=2010A=2A

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