First slide

Kirchoff's Law

Question

In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is :

Moderate

A

+ 2V
B

– 2V
C

+ 1V
D

– 1V

Solution

$\begin{array}{l} A p p l y i n g K J R a t D _{2} \\ - 1 - i = 0 \\ \Rightarrow i = 1 A \\ N o w, a p p l y i n g K V L i n b r a n c h A C D B \\ V_{A} + 1 + 2 (1) - 2 = V_{B} \\ \Rightarrow V_{B} - V_{A} = 1 + 2 (1) - 2 = + 1 v o l t \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App