In the circuit given in figure, VC=50 V and R=50Ω The values of C and VR are

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3.3 mF, 60 V

104μF, 98V

52μF,98V

2μF,60V

answer is B.

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Detailed Solution

VC2+VR2=V2502+VR2=1102⇒VR=160×60=98VThen, Iv=160×6050(∴R=50Ω)Also, Iv=110R2+XC2 ∴9850=110502+XC2Flux XC and now using XC=1ωC, we get C=104 μF

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