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In the circuit given in figure, VC=50 V and R=50Ω The values of C and VR are

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a
3.3 mF, 60 V
b
104μF, 98V
c
52μF,98V
d
2μF,60V

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detailed solution

Correct option is B

VC2+VR2=V2502+VR2=1102⇒VR=160×60=98VThen, Iv=160×6050(∴R=50Ω)Also, Iv=110R2+XC2 ∴9850=110502+XC2Flux XC and now using XC=1ωC, we get C=104 μF

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