Questions
In the circuit given in figure, and The values of C and VR are
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a
3.3 mF, 60 V
b
104μF, 98V
c
52μF,98V
d
2μF,60V
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Correct option is B
VC2+VR2=V2502+VR2=1102⇒VR=160×60=98VThen, Iv=160×6050(∴R=50Ω)Also, Iv=110R2+XC2 ∴9850=110502+XC2Flux XC and now using XC=1ωC, we get C=104 μF
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