A circuit has a section AB shown in figure. The emf of the cell is $$10$$ V and the capacitors have capacitances $$C1=1$$μF and $$C2=2$$μF. The potential difference $$VAB=5V$$. Find the charges on the capacitors (in$$ μ$$C).

Question

A circuit has a section AB shown in figure. The emf of the cell is $$10$$ V and the capacitors have capacitances $$C1=1$$μF and $$C2=2$$μF. The potential difference $$VAB=5V$$. Find the charges on the capacitors (in$$ μ$$C).

Infinity Learn · Accepted Answer

Let the charge on the left plate of the capacitor is q, hence the charge on right plate of capacitor C₂ will be -q as charge supplied by negative plate of capacitor will be -q.

Moving from point A in the section of circuit AB

$V_{A} - \frac{q}{1} + 10 - \frac{q}{2} = V_{B}$

$V_{A} - V_{B} = q + \frac{q}{2} - 10 \Rightarrow 5 = \frac{3}{2} q - 10$

Hence the charges on the capacitors $q = 10 μC$

Kirchhoff's rules for capacitors

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A circuit has a section AB shown in figure. The emf of the cell is 10 V and the capacitors have capacitances $C_{1} = 1 μF$ and $C_{2} = 2 μF$ . The potential difference $V_{AB} = 5 V .$ Find the charges on the capacitors (in $μ$ C).

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Kirchhoff's rules for capacitors

Remember concepts with our Masterclasses.

A circuit has a section AB shown in figure. The emf of the cell is 10 V and the capacitors have capacitances C1=1μF and C2=2μF. The potential difference VAB=5V. Find the charges on the capacitors (in μC).

Ready to Test Your Skills?

free study material

A circuit has a section AB shown in figure. The emf of the cell is 10 V and the capacitors have capacitances $C_{1} = 1 μF$ and $C_{2} = 2 μF$ . The potential difference $V_{AB} = 5 V .$ Find the charges on the capacitors (in $μ$ C).