First slide

Kirchhoff's rules for capacitors

Question

In the circuit show in the figure, the total charge is $750 μ C$ and the voltage across capacitor $C_{2}$ is 20 V. Then the charge on capacitor $C_{2}$ is :

Easy

A

$160 μ C$
B

$590 μ C$
C

$650 μ C$
D

$450 μ C$

Solution

$\begin{array}{l} Q = Q_{2} + Q_{3} \\ \Rightarrow 750 = Q_{2} + 8 (20) \\ \Rightarrow Q_{2} = 590 μ C \end{array}$

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