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In the circuit shown below E₁ = 4.0 V, $R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω, and R_{3} = 2 Ω$ current I₁ is :

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Correct option is B

1rel =14+12req =4/3ΩEeq=ε1r1+ε2r2req =64+02(4/3)=2VI1=4V+Eeq 2Ω+req=4+22+4/3A=1.8A

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In the circuit shown below E1 = 4.0 V, R1=2Ω,E2=6.0V,R2=4Ω, and R3=2Ω current I1 is :

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In the circuit shown below E₁ = 4.0 V, $R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω, and R_{3} = 2 Ω$ current I₁ is :