Q.

In the circuit shown below E1 = 4.0 V, R1=2Ω,E2=6.0V,R2=4Ω, and R3=2Ω current I1 is :

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a

1.6 A

b

1.8 A

c

1.25 A

d

1.0 A

answer is B.

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Detailed Solution

1rel =14+12req =4/3ΩEeq=ε1r1+ε2r2req =64+02(4/3)=2VI1=4V+Eeq 2Ω+req=4+22+4/3A=1.8A
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