First slide

KVL

Question

In the circuit shown below E₁ = 4.0 V, $R_{1} = 2 Ω$ E₂ = 6.0 V, $R_{2} = 4 Ω$ and $R_{3} = 2 Ω .$ The current I₁ is:

Moderate

A

1.6 A
B

1.8 A
C

1.25 A
D

1.0 A

Solution

For loop ABEFA
$- 2 (I_{2} - I_{1}) - 4 I_{2} + 6 = 0 \dots (1)$
$2 I_{1} - 6 I_{2} + 6 = 0$
$or I_{1} = 3 (I_{2} - 1) \dots (1)$
For loop BCDEB
$4 - 2 I_{1} + 2 (I_{2} - I_{1}) = 0$
$I_{2} = 2 I_{1} - 2 \dots (2)$
Put in (1)
$I_{1} = 3 \{(2 I_{1} - 2) - 1\}$
$I_{1} = 6 I_{1} - 9 OR I_{1} = 1.8 A$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App