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In the circuit shown below $E_{1} = 4 .0 V, R_{1} = 2 Ω, E_{2} = 6 .0 V, R_{2} = 4 Ω and R_{3} = 2 Ω .$ The current i₁ is

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Correct option is B

Applying Kirchhoff's law for the loops (l) and (2) as shown in figure.For loop (1),−2i1−2i1−i2+4=0 ⇒2i1−i2=2 ...iFor loop (2),−2i1−i2+4i2−6=0 ⇒−i1+3i2=3 ...iiOn solving equations (i) and (ii), i1 = 1.8 A

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In the circuit shown below E1=4.0 V, R1 =2 Ω, E2=6.0 V, R2 = 4 Ω and R3 = 2 Ω. The current i1 is

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In the circuit shown below $E_{1} = 4 .0 V, R_{1} = 2 Ω, E_{2} = 6 .0 V, R_{2} = 4 Ω and R_{3} = 2 Ω .$ The current i₁ is