In the circuit shown below E1=4.0 V, R1 =2 Ω, E2=6.0 V, R2 = 4 Ω and R3 = 2 Ω. The current i1 is
1.6 A
1.8 A
1.25 A
1.0 A
Applying Kirchhoff's law for the loops (l) and (2) as shown in figure.
For loop (1),
−2i1−2i1−i2+4=0 ⇒2i1−i2=2 ...i
For loop (2),
−2i1−i2+4i2−6=0 ⇒−i1+3i2=3 ...ii
On solving equations (i) and (ii), i1 = 1.8 A