The circuit shown below is working as a 8 V dc regulated voltage source. When 12V is used as input, the power dissipated (in mW )in each diode is; ( considering both Zener diodes are identical)____

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is 0040.00.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

Total voltage drop across both resistors is 4V.Current in the circuit i=4400=1100A.Voltage drop across each diode is 4V. So, power dissipated in each diode is p=vi =4×1100 =40×10−3 W =40mW

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!