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Q.

The circuit shown below is working  as 6 V dc regulated voltage source when 10 V dc used as input, the power dissipated (in mW) in each diode is ( Consider both zener diodes identical)

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Detailed Solution

Current is the circuit = VR                                          =10-6100+100=150=0.02=2×10−2APotential Drop across each diode = 62 = 3 VPower dissipated in each diode = V I                                              =3×2×10−2=6×10−2=60×10−3W=60mW
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