First slide

Diodes

Question

The circuit shown below is working as 10 V dc regulated voltage source. When 12 V is used as input, the power dissipated (in mW) in each diode is (Consider both Zener diodes are identical)

Moderate

Solution

$C u r r e n t i n t h e c i r c u i t = \frac{V}{R} = \frac{2}{200 + 200} = \frac{2}{400} = 5 \times 10^{- 3} A$
$N o w, p o w e r i n e a c h d i o d e = C u r r e n t \times V o l t a g e a c r o s s e a c h d i o d e$
$= 5 \times 10^{- 3} \times 5 = 25 m W$

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