First slide

KVL

Question

In the circuit shown, calculate the current through 6 V battery.

Difficult

A

(1/4) A
B

(1/8) A
C

(1/2) A
D

None of these

Solution

Equivalent circuit:
$I = \frac{5 - 5}{8} = 0 \Rightarrow V_{A} - V_{B} = 0$
So current will be only in the smaller loop containing 6 V and 4 V battery. So current through 6 V battery $I^{'} = \frac{6 - 4}{4} = \frac{1}{2} A$

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