First slide

Capacitors and capacitance

Question

In the circuit shown, a capacitor of capacitance $3 μ F$ is charged form a battery of emf 6 V with switch connected to terminal P. The switch is now connected to Q. This charges the $6 μ F$ capacitor from the $3 μ F$ one. What is the new potential difference across combination?

Moderate

A

1 V
B

2 V
C

4 V
D

6 V

Solution

Initially at switch position Q, by conservation of charge, the voltage V across the two capacitors is thus given by
$q = q_{1} + q_{2} = C V_{1} + C_{2} V = (C_{1} + C_{2}) V$
or $18 = (3 + 6) V$
or $V = (18 / 9) = 2 V$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App