In the circuit shown, the capacitor is initially charged to a potential V. At t=0 .switch S is closed. When magnetic energy stored to the inductor is equal to the electric energy stored in the capacitor, current flowing in the circuit is.
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a
VC2L
b
VCL
c
2VCL
d
V2LC
answer is A.
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Detailed Solution
UB=12Li2, UE=UB=12Li2Conserving energy ,12Li2+12Li2=12CV2⇒i = VC2L