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In the circuit shown, charge on the 5 $μ F$ capacitor is :

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16.36 μC

5.45 μC

10.90 μC

18.00 μC

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detailed solution

Correct option is A

Applying KJR q=q1+q2Applying KLR 6−q12−q5=0And 6−q24−q5=0⇒q2=2q1⇒q=3q1Thus , 6−q6−q5=0⇒1130q=6⇒q=18011μC=16.36μC

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In the circuit shown, charge on the 5μF capacitor is :

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

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In the circuit shown, charge on the 5 $μ F$ capacitor is :