In the circuit shown, charge on the 5μF capacitor is :
16.36 μC
5.45 μC
10.90 μC
18.00 μC
Applying KJR
q=q1+q2Applying KLR
6−q12−q5=0
And
6−q24−q5=0⇒q2=2q1⇒q=3q1Thus , 6−q6−q5=0⇒1130q=6⇒q=18011μC=16.36μC