In the circuit shown a current through 20Ω resistor equals
3/2 A
2/3 A
5/2 A
9/2 A
Let x be the current through 20 Ω resistor and y be the current through 10 Ω resistor.
Applying KVL, 10-10y=0⇒y=1 A
Also, 20-20x+10y=0⇒20-20x+10×1=0⇒x=3/2 A