In the circuit shown, the currents in 4 Ω and 8 Ω resistances are
2.5 A, 0
5 A, 0
2.5 A, 403 A
5 A, 803 A
Since battery is in parallel with 4 Ω resistance, it carries current
I=104=2.5A
In open loop a1a d e g,
Va1+10−10=0⇒Va1=0
Thus, all resistances, i.e, 2 Ω, 2 Ω, 1 Ω and 8 Ω, connected between a1 and g, carry zero current.