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Questions  

In the circuit shown, the equivalent capacitance between points A and B is 

 

a
1 μF
b
2 μF
c
23 μF
d
4 μF

detailed solution

Correct option is B

The circuit can be redrawn as shown below, ∴ CAB=(1+2)×(5+1)(1+2)(5+1)μF=2 μF

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