First slide

KVL

Question

In the circuit shown in the Fig, if the potential at point A is taken to be zero, the potential at point B is :

Easy

A

+1 V
B

- 1 V
C

+ 2 V
D

-2 V

Solution

By applying KVL along path ACDB
$V_{A} + 1 + 2 x 1 - 2 = V_{B} \Rightarrow V_{B} = 1 V$

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