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In the circuit shown in Fig, $R_{3}$ is a variable resistance. As the value $R_{3}$ is changed, current I through the cell varies as shown. Obviously, the variation is asymptotic, i.e., I ➔ 6A as $R_{3} \to \infty$ . Resistances $R_{1} and R_{2}$ are, respectively :

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4 Ω, 2 Ω

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detailed solution

Correct option is C

From given situation36R1+R2=9 and 36R1+2R2=6⇒R2=2 Ω and R1=2 Ω

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In the circuit shown in Fig, R3 is a variable resistance. As the value R3 is changed, current I through the cell varies as shown. Obviously, the variation is asymptotic, i.e., I ➔ 6A as R3 →∞. Resistances R1 and R2 are, respectively :

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Ready to Test Your Skills?

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In the circuit shown in Fig, $R_{3}$ is a variable resistance. As the value $R_{3}$ is changed, current I through the cell varies as shown. Obviously, the variation is asymptotic, i.e., I ➔ 6A as $R_{3} \to \infty$ . Resistances $R_{1} and R_{2}$ are, respectively :