In the circuit shown in fig. the rate of heat produced in the 5 ohm resistor is 20 Js-1
The current in the 6 ohm resistor is 1 A.
The current in the 5 ohm resistor is 2 A.
The rate of heat produced in the 4 ohm resistor is 4 Js-1.
All of these are correct
for 5 ohm resistor i25= 20 i=2 A current in the upper branch will be 1 A as resistance is double 10 ohm in 4 ohm resitance power consumption 12 4 = 4 Js-1