In the circuit shown in fig. the rate of heat produced in the 5 Ω resistor is 20 J s-1.
The current in the 6 Ω resistor is 1 A.
The current in the 5 Ω resistor is 2 A.
The rate of heat produced in the 4 Ω resistor is 4 J s-1.
All of these
i2R=20i2=4i=2A
Current in other branch where R=10ΩI = 1ARate of heat produced in 4ΩH=i2R=124=4