In the circuit shown in the figure, the ac source gives a voltage V=20cos(2000 t). Neglecting source resistance, the voltmeter and ammeter reading will be
0V, 0.47A
1.68V, 0.47A
0V, 1.4 A
5.6V, 1.4 A
Z=(R)2+(XL−XC)2;
R=10 Ω, XL=ωL=2000×5×10−3=10 Ω
XC=1ωC=12000×50×10−6=10 Ω i.e. Z=10 Ω
Maximum current i0=V0Z=2010=2A
Hence irms=22=1.4 A
and Vrms=4×1.41= 5.64V