In the circuit shown in the figure, the ac source gives a voltage V=20cos(2000 t). Neglecting source resistance, the voltmeter and ammeter reading will be

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0V, 0.47A

1.68V, 0.47A

0V, 1.4 A

5.6V, 1.4 A

answer is D.

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Detailed Solution

Z=(R)2+(XL−XC)2; R=10Ω,XL=ωL=2000×5×10−3=10ΩXC=1ωC=12000×50×10−6=10Ω i.e. Z=10Ω Maximum current i0=V0Z=2010=2A Hence irms=22=1.4 A

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