In the circuit shown in the figure, the AC source gives a voltage V=20cos(2000t). Neglecting source resistance, the voltmeter and ammeter reading will be

Z=(R)2+XL−XC2R=10Ω, XL=ωL=2000 × 5 × 10−3=10 ΩXC=1ωC=12000×50×10−6=10 Ω,  i.e.,  Z=10 Ω⇒Z=102+(10−10)2=10 ΩMaximum current, i0=V0Z=2010=2 AHence, irms=22=1.41 Aand     Vrms=4 × 1.41=5.64 V