In the circuit shown in figure, the charge on the 5  μF capacitor will be

Potential difference across upper branch is 6 VV2=V(C1C1+C2)=10[33+7]=3  VHence, potential difference across 5  μF capacitor is 3 V. Thus, charge on  5  μFcapacitor isQ5  μF=5×3=15  μC