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Q.

In the circuit shown in figure, a conducting wire HE is moved with a constant speed v toward left. The complete circuit is placed in a uniform magnetic field B⇀ perpendicular to the plane of the circuit inward. The current tn HKDE is

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a

clockwise

b

anticlockwise

c

alternating

d

zero

answer is D.

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Detailed Solution

Potential difference across capacitorV = Bvl = constantTherefore, charge stored in the capacitor is also constant. Thus, current through the capacitor is zero.∵i=dqdt
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In the circuit shown in figure, a conducting wire HE is moved with a constant speed v toward left. The complete circuit is placed in a uniform magnetic field B⇀ perpendicular to the plane of the circuit inward. The current tn HKDE is