Questions

For the circuit shown in the figure, the current I will be

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0.5 A

0.75 A

1 A

1.5 A

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detailed solution

Correct option is C

By KVL in a closed loop ABCDA,VA – I × 4 – I × 1 + 4 – I × 1 + 2 = VA–6I + 6 = 0 I = 1 A

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