For the circuit shown in figure, current in inductance is 0.8 A while that in capacitance is 0.6 A. What is the current drawn from the source?

If an ac sourceE=E0 sinωtis applied across an inductance and capacitance in parallel, the current in inductance will lag theapplied voltage while that across the capacitor will lead, and so,IL=E0XLsinωt-π2 = -0.82 cosωtIc=VXCsinωt+π2 = 0.62 cosωtSo the current drawn from the sourceI=IL+IC=-0.22cosωtIrms=I02=0.222=0.2A