In the circuit shown in figure, current through the conductor BC is
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a
2A
b
4A
c
3A
d
6A
answer is D.
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Detailed Solution
The resistance 2Ω is short circuited. therefore current through 3Ω, i3=123A = 4A and current through 6Ω, i6=126A = 2A.Current through 2Ω is zero and current through BC is (4 + 2) A i.e. 6 A.