First slide

Capacitance

Question

In the circuit as shown in figure, the effective capacitance between A and B is

Easy

A

$8 μF$
B

$4 μF$
C

$2 μF$
D

$3 μF$

Solution

The capacitor C₄ and Cu are in parallel. Their equivalent capacitance C' = 2 +2 = 4 $μ$ F. Now C' is in series with C₃. Their equivalent capacitance is given by
$\frac{1}{C^{''}} = \frac{1}{4} + \frac{1}{4} = \frac{1}{2} or C^{''} = 2 μF$
Capacitance C₁ and C₂ are in series. Their equivalent capacitance C"' = 2 $μ$ F
The capacitance a cross AB is given by $C =2 μF +2 μF =4 μF$ .

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