Q.
For the circuit shown in figure, the equivalent resistance between A and C is
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a
1211r
b
1311r
c
1411r
d
1511r
answer is D.
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Detailed Solution
At junction E of R:I1+I3+I4=I2−I3 or I1−I2+2I3+I4=0Loop AFBA or loop ECDErI1=rI2+rI3 or I1=I2+I3Loop BEFB or loop EDFEr(I2−I3)+rI4=rI3 or I2-2I3+I4=0Loop AFDCMA or ABECMAV=rI1+r(I2−I3)+rI2=rI1+2rI2−rI3Solve to get I1=2V/5r, I2=V/3rReq=VI=VI1+I2=V2V/5r+V/3r=15r11
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