First slide

KVL

Question

In the circuit shown in figure, the galvanometer G shows zero deflection. If the batteries A and B have negligible internal resistance, the value of the resistance of resistor R will be

Moderate

A

$1000 Ω$
B

$500 Ω$
C

$100 Ω$
D

$200 Ω$

Solution

Current through R is $12 / (500 + R)$
Voltage across R is $\frac{12 R}{500 + R}$
Since Galvanometer shows zero deflection.
So $\frac{12 R}{500 + R} = 2.$

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