In the circuit shown in the figure , if the potential at point A is taken to be zero. The potential at point B is

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-2V

+1V

-1V

+2V

answer is B.

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Detailed Solution

Apply junction rule at Di+1=2 ⇒i=1AUse open loop Kirchhoff B to A [Path BDCA] :⇒VB+2−i×2−1=VA ⇒VB+2−1×2−1=0 ⇒VB=1V

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