First slide

Kirchoff's Law

Question

In the circuit shown in the figure , if the potential at point A is taken to be zero. The potential at point B is

Easy

A

-2V
B

+1V
C

-1V
D

+2V

Solution

Apply junction rule at D
$i + 1 = 2 \Rightarrow i = 1 A$
Use open loop Kirchhoff B to A [Path BDCA] :
$\Rightarrow V_{B} + 2 - i \times 2 - 1 = V_{A} \Rightarrow V_{B} + 2 - 1 \times 2 - 1 = 0 \Rightarrow V_{B} = 1 V$

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